分級(jí)變速主傳動(dòng)系統(tǒng)的設(shè)計(jì)【Nmin=53rmin Nmax=600rmin Z=8 φ=1.41 P=4KW n=1440rmin】
分級(jí)變速主傳動(dòng)系統(tǒng)的設(shè)計(jì)【Nmin=53rmin Nmax=600rmin Z=8 φ=1.41 P=4KW n=1440rmin】,Nmin=53rmin Nmax=600rmin Z=8 φ=1.41 P=4KW n=1440rmin,分級(jí)變速主傳動(dòng)系統(tǒng)的設(shè)計(jì)【Nmin=53rmin,Nmax=600rmin,Z=8,φ=1.41,分級(jí)
哈爾濱理工大學(xué)
課 程 設(shè) 計(jì)
題 目:機(jī)械系統(tǒng)設(shè)計(jì)課程設(shè)計(jì)
院 、 系:機(jī)械動(dòng)力工程學(xué)院
班 級(jí):機(jī)械
姓 名:
學(xué) 號(hào):
指導(dǎo)教師:
摘 要
《機(jī)械系統(tǒng)設(shè)計(jì)》課程設(shè)計(jì)內(nèi)容有理論分析與設(shè)計(jì)計(jì)算,圖樣技術(shù)設(shè)計(jì)和技術(shù)文件編制三部分組成。
1、理論分析與設(shè)計(jì)計(jì)算:
(1)機(jī)械系統(tǒng)的方案設(shè)計(jì)。設(shè)計(jì)方案的分析,最佳功能原理方案的確定。
(2)根據(jù)總體設(shè)計(jì)參數(shù),進(jìn)行傳動(dòng)系統(tǒng)運(yùn)動(dòng)設(shè)計(jì)和計(jì)算。
(3)根據(jù)設(shè)計(jì)方案和零部件選擇情況,進(jìn)行有關(guān)動(dòng)力計(jì)算與校核。
2、圖樣技術(shù)設(shè)計(jì):
(1)選擇系統(tǒng)中的主要組件。
(2)圖樣的設(shè)計(jì)與繪制。
3、編制技術(shù)文件:
(1)對(duì)于課程設(shè)計(jì)內(nèi)容進(jìn)行自我技術(shù)經(jīng)濟(jì)評(píng)價(jià)。
(2)編制設(shè)計(jì)計(jì)算說(shuō)明書(shū)。
關(guān)鍵詞 分級(jí)變速;傳動(dòng)系統(tǒng)設(shè)計(jì),傳動(dòng)副,結(jié)構(gòu)網(wǎng),結(jié)構(gòu)式,齒輪模數(shù),傳動(dòng)比,計(jì)算轉(zhuǎn)速
目錄
摘 要 2
目錄 3
一、課程設(shè)計(jì)目的 4
二、課程設(shè)計(jì)題目,主要技術(shù)參數(shù)和技術(shù)要求分級(jí)、 4
三、運(yùn)動(dòng)設(shè)計(jì) 4
1.確定極限轉(zhuǎn)速,轉(zhuǎn)速數(shù)列,結(jié)構(gòu)網(wǎng)和結(jié)構(gòu)式 4
2.主傳動(dòng)轉(zhuǎn)速圖和傳動(dòng)系統(tǒng)圖 6
3.計(jì)算齒輪齒數(shù) 7
四、動(dòng)力計(jì)算 9
1.傳動(dòng)件的計(jì)算轉(zhuǎn)速 9
2.傳動(dòng)軸和主軸的軸徑設(shè)計(jì) 9
3.計(jì)算齒輪模數(shù)及尺寬,分度圓直徑 10
4.帶輪設(shè)計(jì) 11
五、主要零部件選擇 13
1.軸承的選取 13
2.鍵的選取 13
六、校核 14
1.齒輪校核 14
2 .主軸彎曲剛度校核 16
3.軸承校核 16
4.潤(rùn)滑與密封 16
七、結(jié)束語(yǔ) 17
八、參考文獻(xiàn) 17
一、課程設(shè)計(jì)目的
《機(jī)械系統(tǒng)設(shè)計(jì)》課程設(shè)計(jì)是在學(xué)完本課程后,進(jìn)行一次學(xué)習(xí)設(shè)計(jì)的綜合性練習(xí)。通過(guò)課程設(shè)計(jì),使學(xué)生能夠運(yùn)用所學(xué)過(guò)的基礎(chǔ)課,技術(shù)基礎(chǔ)課和專(zhuān)業(yè)課的有關(guān)理論知識(shí),及生產(chǎn)等實(shí)踐技能,達(dá)到鞏固,加深和拓展所學(xué)知識(shí)的目的。通過(guò)課程設(shè)計(jì),分析比較機(jī)械系統(tǒng)中的某些典型結(jié)構(gòu),進(jìn)行選擇和改進(jìn);結(jié)合結(jié)構(gòu)設(shè)計(jì),進(jìn)行設(shè)計(jì)計(jì)算并編寫(xiě)技術(shù)文件;完成系統(tǒng)主轉(zhuǎn)動(dòng)設(shè)計(jì),達(dá)到學(xué)習(xí)設(shè)計(jì)步驟和方法的目的。通過(guò)設(shè)計(jì),掌握查閱相關(guān)工程設(shè)計(jì)手冊(cè),設(shè)計(jì)標(biāo)準(zhǔn)和資料的方法,達(dá)到積累設(shè)計(jì)知識(shí)和設(shè)計(jì)技巧,提高學(xué)生設(shè)計(jì)能力的目的。通過(guò)設(shè)計(jì),使學(xué)生獲得機(jī)械系統(tǒng)基本設(shè)計(jì)技能的訓(xùn)練,提高分析和解決工程技術(shù)問(wèn)題的能力,并為進(jìn)行機(jī)械系統(tǒng)設(shè)計(jì)創(chuàng)造一定的條件。
二、課程設(shè)計(jì)題目,主要技術(shù)參數(shù)和技術(shù)要求分級(jí)、
分級(jí)變速主傳動(dòng)系統(tǒng)
設(shè)計(jì)題目1:
技術(shù)參數(shù):
Nmin=53r/min;Nmax=600r/min;
Z=8級(jí);公比為1.41;電動(dòng)機(jī)功率P=4kW;電機(jī)轉(zhuǎn)速n=1440r/min
三、運(yùn)動(dòng)設(shè)計(jì)
1.確定極限轉(zhuǎn)速,轉(zhuǎn)速數(shù)列,結(jié)構(gòu)網(wǎng)和結(jié)構(gòu)式
(1)確定極限轉(zhuǎn)速,公比、變速級(jí)數(shù)
Nmin=53r/min;Nmax=600r/min;Z=8級(jí);公比為1.41
(2) 轉(zhuǎn)速數(shù)列:
53r/min,75r/min,106r/min,150r/min,212r/min,300r/min,425r/min,
600r/min共8級(jí)
(3)確定極限轉(zhuǎn)速:
Rn=Nmax/Nmin=600/53=11.32
(4)確定結(jié)構(gòu)網(wǎng)和結(jié)構(gòu)式
(1)寫(xiě)傳動(dòng)結(jié)構(gòu)式:主軸轉(zhuǎn)速級(jí)數(shù)Z=8. 結(jié)構(gòu)式8=21×22×23
(2)畫(huà)結(jié)構(gòu)網(wǎng):
Z=21×22×23
2.主傳動(dòng)轉(zhuǎn)速圖和傳動(dòng)系統(tǒng)圖
選擇電動(dòng)機(jī):采用Y系列封閉自扇冷式鼠籠型三相異步電動(dòng)機(jī)繪制轉(zhuǎn)速圖。
8=21×22×23
傳動(dòng)系統(tǒng)圖
3.計(jì)算齒輪齒數(shù)
(1)、齒數(shù)計(jì)算
基本組傳動(dòng)比分別為1/1.41,1/2
Sz= 72 75 84 93 96 ……
取Sz=72,小齒輪齒數(shù)分別為:30、24
Z1 / Z1’ =30/42, Z2 / Z2’ =24/48
第二擴(kuò)大組傳動(dòng)比分別為1/1.41,1/2.8
取Sz=87,小齒輪齒數(shù):36、23
Z4/Z4’=36/51,Z5/Z5’=23/64
第三擴(kuò)大組傳動(dòng)比分別為1.41:1,1/2
取Sz=96,小齒輪齒數(shù):40、25
Z4/Z4’=40/56,Z5/Z5’=25/71
(2)校核各級(jí)轉(zhuǎn)速的轉(zhuǎn)速誤差
實(shí)際傳動(dòng)比所造成主軸轉(zhuǎn)速誤差
,其中為實(shí)際轉(zhuǎn)速,n為標(biāo)準(zhǔn)轉(zhuǎn)速。
N
600
300
212
150
106
75
53
n
610.6
310
212.3
150
107.7
76.1
54.2
誤差值
2.1%
1.4%
2.1%
0
2.1%
1.2%
1.9%
以上誤差值均小于4.1% 故合格.
四、動(dòng)力計(jì)算
4.1 帶傳動(dòng)設(shè)計(jì)
輸出功率P=4kW,轉(zhuǎn)速n1=1440r/min,n2=850r/min
4.1.1計(jì)算設(shè)計(jì)功率Pd
表4 工作情況系數(shù)
工作機(jī)
原動(dòng)機(jī)
ⅰ類(lèi)
ⅱ類(lèi)
一天工作時(shí)間/h
10~16
10~16
載荷
平穩(wěn)
液體攪拌機(jī);離心式水泵;通風(fēng)機(jī)和鼓風(fēng)機(jī)();離心式壓縮機(jī);輕型運(yùn)輸機(jī)
1.0
1.1
1.2
1.1
1.2
1.3
載荷
變動(dòng)小
帶式運(yùn)輸機(jī)(運(yùn)送砂石、谷物),通風(fēng)機(jī)();發(fā)電機(jī);旋轉(zhuǎn)式水泵;金屬切削機(jī)床;剪床;壓力機(jī);印刷機(jī);振動(dòng)篩
1.1
1.2
1.3
1.2
1.3
1.4
載荷
變動(dòng)較大
螺旋式運(yùn)輸機(jī);斗式上料機(jī);往復(fù)式水泵和壓縮機(jī);鍛錘;磨粉機(jī);鋸木機(jī)和木工機(jī)械;紡織機(jī)械
1.2
1.3
1.4
1.4
1.5
1.6
載荷
變動(dòng)很大
破碎機(jī)(旋轉(zhuǎn)式、顎式等);球磨機(jī);棒磨機(jī);起重機(jī);挖掘機(jī);橡膠輥壓機(jī)
1.3
1.4
1.5
1.5
1.6
1.8
根據(jù)V帶的載荷平穩(wěn),兩班工作制(16小時(shí)),查《機(jī)械設(shè)計(jì)》P296表4,
取KA=1.1。即
4.1.2選擇帶型
普通V帶的帶型根據(jù)傳動(dòng)的設(shè)計(jì)功率Pd和小帶輪的轉(zhuǎn)速n1按《機(jī)械設(shè)計(jì)》P297圖13-11選取。
根據(jù)算出的Pd=4.4kW及小帶輪轉(zhuǎn)速n1=1440r/min ,查圖得:dd=80~100可知應(yīng)選取A型V帶。
4.1.3確定帶輪的基準(zhǔn)直徑并驗(yàn)證帶速
由《機(jī)械設(shè)計(jì)》P298表13-7查得,小帶輪基準(zhǔn)直徑為80~100mm
則取dd1= 100mm> ddmin.=75 mm(dd1根據(jù)P295表13-4查得)
表3. V帶帶輪最小基準(zhǔn)直徑
槽型
Y
Z
A
B
C
D
E
20
50
75
125
200
355
500
由《機(jī)械設(shè)計(jì)》P295表13-4查“V帶輪的基準(zhǔn)直徑”,得=160mm
① 誤差驗(yàn)算傳動(dòng)比: (為彈性滑動(dòng)率)
誤差 符合要求
② 帶速
滿足5m/s300mm,所以宜選用E型輪輻式帶輪。
總之,小帶輪選H型孔板式結(jié)構(gòu),大帶輪選擇E型輪輻式結(jié)構(gòu)。
帶輪的材料:選用灰鑄鐵,HT200。
4.1.7確定帶的張緊裝置
選用結(jié)構(gòu)簡(jiǎn)單,調(diào)整方便的定期調(diào)整中心距的張緊裝置。
4.1.8計(jì)算壓軸力
由《機(jī)械設(shè)計(jì)》P303表13-12查得,A型帶的初拉力F0=118.14N,上面已得到=171.81o,z=4,則
對(duì)帶輪的主要要求是質(zhì)量小且分布均勻、工藝性好、與帶接觸的工作表面加工精度要高,以減少帶的磨損。轉(zhuǎn)速高時(shí)要進(jìn)行動(dòng)平衡,對(duì)于鑄造和焊接帶輪的內(nèi)應(yīng)力要小, 帶輪由輪緣、腹板(輪輻)和輪轂三部分組成。帶輪的外圈環(huán)形部分稱(chēng)為輪緣,輪緣是帶輪的工作部分,用以安裝傳動(dòng)帶,制有梯形輪槽。由于普通V帶兩側(cè)面間的夾角是40°,為了適應(yīng)V帶在帶輪上彎曲時(shí)截面變形而使楔角減小,故規(guī)定普通V帶輪槽角 為32°、34°、36°、38°(按帶的型號(hào)及帶輪直徑確定),輪槽尺寸見(jiàn)表7-3。裝在軸上的筒形部分稱(chēng)為輪轂,是帶輪與軸的聯(lián)接部分。中間部分稱(chēng)為輪幅(腹板),用來(lái)聯(lián)接輪緣與輪轂成一整體。
表 普通V帶輪的輪槽尺寸(摘自GB/T13575.1-92)
項(xiàng)目
?
符號(hào)
槽型
Y
Z
A
B
C
D
E
基準(zhǔn)寬度
b p
5.3
8.5
11.0
14.0
19.0
27.0
32.0
基準(zhǔn)線上槽深
h amin
1.6
2.0
2.75
3.5
4.8
8.1
9.6
基準(zhǔn)線下槽深
h fmin
4.7
7.0
8.7
10.8
14.3
19.9
23.4
槽間距
e
8 ± 0.3
12 ± 0.3
15 ± 0.3
19 ± 0.4
25.5 ± 0.5
37 ± 0.6
44.5 ± 0.7
第一槽對(duì)稱(chēng)面至端面的距離
f min
6
7
9
11.5
16
23
28
最小輪緣厚
5
5.5
6
7.5
10
12
15
帶輪寬
B
B =( z -1) e + 2 f ? z —輪槽數(shù)
外徑
d a
輪 槽 角
32°
對(duì)應(yīng)的基準(zhǔn)直徑 d d
≤ 60
-
-
-
-
-
-
34°
-
≤ 80
≤ 118
≤ 190
≤ 315
-
-
36°
60
-
-
-
-
≤ 475
≤ 600
38°
-
> 80
> 118
> 190
> 315
> 475
> 600
極限偏差
± 1
± 0.5
V帶輪按腹板(輪輻)結(jié)構(gòu)的不同分為以下幾種型式:
(1) 實(shí)心帶輪:用于尺寸較小的帶輪(dd≤(2.5~3)d時(shí)),如圖7 -6a。
(2) 腹板帶輪:用于中小尺寸的帶輪(dd≤ 300mm 時(shí)),如圖7-6b。
(3) 孔板帶輪:用于尺寸較大的帶輪((dd-d)> 100 mm 時(shí)),如圖7 -6c 。
(4) 橢圓輪輻帶輪:用于尺寸大的帶輪(dd> 500mm 時(shí)),如圖7-6d。
(a) (b) (c) (d)
圖7-6 帶輪結(jié)構(gòu)類(lèi)型
根據(jù)設(shè)計(jì)結(jié)果,可以得出結(jié)論:小帶輪選擇實(shí)心帶輪,如圖(a),大帶輪選擇腹板帶輪如圖(b)
1.傳動(dòng)件的計(jì)算轉(zhuǎn)速
軸 序 號(hào)
電動(dòng)機(jī)(0)
I軸
II軸
III軸
IV軸
計(jì)算轉(zhuǎn)速r/min
1440
850
600
212
75
最小齒輪的計(jì)算轉(zhuǎn)速如下:
Z1
Z1’
Z2
Z2’
Z3
Z3’
Z4
Z4’
Z5
Z5’
Z6
Z6’
850
600
850
600
600
212
600
212
212
75
212
75
2.傳動(dòng)軸和主軸的軸徑設(shè)計(jì)
(1)傳動(dòng)軸軸徑初定
Ⅰ軸:p=4kw,n=850r/min,=0.5帶入公式:
=29.6mm,圓整取d=30mm
Ⅱ軸:p=4kw,n=355r/min,=0.5
=35.3mm,圓整取d=36mm
III軸:p=4kw,n=125r/min,=0.5帶入公式:
=45.8mm,圓整取d=46mm
(2)主(IV)軸軸頸直徑確定:
查表4-9選擇主軸前端直徑D1=80mm,后端直徑D2=64mm
軸承內(nèi)徑d/D小于0.7 則取d=50mm
材料:45鋼。熱處理:調(diào)質(zhì)Hre22-28
主軸懸伸量:a/D1=1.25--2.5 a=(1.25—2.5)D1=(1.25—2.5)x(80+64/2)=90—180 取a=120mm
最佳跨距
3.計(jì)算齒輪模數(shù)及尺寬,分度圓直徑
(1)計(jì)算齒輪模數(shù)
40Gr整體淬火 []=650mpa
mj=16338 3
Nd—驅(qū)動(dòng)電動(dòng)機(jī)功率
u---大齒輪與小齒輪齒數(shù)比
Z1--小齒輪齒數(shù)
m----齒寬系數(shù)m=B/m=6-10 取m=8
nj----計(jì)算齒輪的計(jì)算轉(zhuǎn)速
[]---許用接觸應(yīng)力
a).u=z1/z1’=24/48,nj =850r/min
mj=16338 3=1.85 取m1=2
b).u=z2/z2’=23/64,nj =300r/min
mj=16338 3=2.6 取m2=3
c).u=z3/z3’=25/71,nj =125r/min
mj=16338 3=2.72取m3=3
(2)計(jì)算齒輪分度圓及尺寬
d1=m1z1=232=64mm d1′=m1z1′=242=84mm
d2=m2z2=224=48mm d2′=m2z2′=248=96mm
d3=m3z3=336=108mm d3′=m3z3′=351=153mm
d4=m4z4=323=69mm d4′=m4z4′=364=192mm
d5=m5z5=340=120mm d5′=m5z5′=356=168mm
d6=m6z6=325=75mm d6′=m6z6′=371=213mm
B12=m=82=16mm B34=m=83=24mm B56=m=83=24mm
五、主要零部件選擇
1.軸承的選取
(1)帶輪:選用深溝球軸承,型號(hào):6205
(2)一軸:選用深溝球軸承,型號(hào):6205
(3)二軸:采用深溝球軸承,型號(hào):6206
(4)三軸:采用深溝球軸承,型號(hào):6208
(5)主軸:主軸是傳動(dòng)系統(tǒng)之中最為關(guān)鍵的部分,因此應(yīng)該合理的選擇軸承。
從主軸末端到前端依次選擇軸承為角接觸軸承,型號(hào):7012C;
深溝球軸承,型號(hào):6210
雙列圓柱滾子軸承,型號(hào):NN3000K,
2.鍵的選取
(1)帶輪:選平鍵:87
(2)1軸:選平鍵:87 花鍵:626606
(3)2軸:選平鍵:108 花鍵:832366
(4)3軸:選平鍵:108 花鍵:842468
(5)4軸:選花鍵:8626812
六、校核
1.齒輪校核
齒輪參數(shù)如下:
軸序號(hào)
I
I
II
II
II
II
III
III
III
III
IV
IV
齒輪齒數(shù)Z
30
24
42
48
36
23
51
64
56
25
40
71
模數(shù)M
2
2
2
2
3
3
3
3
3
3
3
3
分度圓d
64
48
84
96
108
69
153
192
168
75
120
213
齒根圓直徑df
55
43
79
91
100.5
61.5
145.5
184.5
160.5
67.5
112.5
205.5
齒頂圓直徑da
64
52
88
100
114
75
159
198
174
81
126
219
(1)一軸到二軸的小齒輪從上表可知為齒數(shù)為29
查設(shè)計(jì)手冊(cè)可得以下數(shù)據(jù):
接觸應(yīng)力:
,
[為傳遞的額定功率(KW)]
將以上數(shù)據(jù)代入公式可得
彎曲應(yīng)力: ,,
將以上數(shù)據(jù)代入公式可得
(2)二軸到三軸的小齒輪從上表可知為齒數(shù)為20
查設(shè)計(jì)手冊(cè)可得以下數(shù)據(jù):
接觸應(yīng)力:
,
[為傳遞的額定功率(KW)]
將以上數(shù)據(jù)代入公式可得
彎曲應(yīng)力:
,
將以上數(shù)據(jù)代入公式可得
2 .主軸彎曲剛度校核
(1)主軸剛度符合要求的條件如下:
a主軸的前端部撓度
b主軸在前軸承處的傾角
c在安裝齒輪處的傾角
(2)計(jì)算如下:
前支撐為雙列圓柱滾子軸承,后支撐為角接觸軸承架立放圓柱滾子軸承跨距L=450mm.
當(dāng)量外徑 de==
主軸剛度:
因?yàn)閐i/de=25/285=0.088<0.7,所以孔對(duì)剛度的影響可忽略;
ks==2kN/mm
剛度要求:主軸的剛度可根據(jù)機(jī)床的穩(wěn)定性和精度要求來(lái)評(píng)定
3.軸承校核
4.潤(rùn)滑與密封
主軸轉(zhuǎn)速高,必須保證充分潤(rùn)滑,一般常用單獨(dú)的油管將油引到軸承處。
主軸是兩端外伸的軸,防止漏油更為重要而困難。防漏的措施有兩種:
1)密封圈——加密封裝置防止油外流。。
2)疏導(dǎo)——在適當(dāng)?shù)牡胤阶龀龌赜吐?,使油能順利地流回到油箱?
七、結(jié)束語(yǔ)
1、本次課程設(shè)計(jì)是針對(duì)《機(jī)械系統(tǒng)設(shè)計(jì)》專(zhuān)業(yè)課程基礎(chǔ)知識(shí)的一次綜合性應(yīng)
用設(shè)計(jì),設(shè)計(jì)過(guò)程應(yīng)用了《機(jī)械制圖》、《機(jī)械原理》、《工程力學(xué)》等。
2、本次課程設(shè)計(jì)充分應(yīng)用了以前所學(xué)習(xí)的知識(shí),并應(yīng)用這些知識(shí)來(lái)分析和解決實(shí)際問(wèn)題。
3、本次課程設(shè)計(jì)進(jìn)一步掌握了一般設(shè)計(jì)的設(shè)計(jì)思路和設(shè)計(jì)切入點(diǎn),同時(shí)對(duì)機(jī)械部件的傳動(dòng)設(shè)計(jì)和動(dòng)力計(jì)算也提高了應(yīng)用各種資料和實(shí)際動(dòng)手的能力。
4、本次課程設(shè)計(jì)進(jìn)一步規(guī)范了制圖要求,掌握了機(jī)械設(shè)計(jì)的基本技能。
5、本次課程設(shè)計(jì)由于學(xué)習(xí)知識(shí)面的狹窄和對(duì)一些概念的理解不夠深刻,以及缺乏實(shí)際設(shè)計(jì)經(jīng)驗(yàn),使得設(shè)計(jì)黨中出現(xiàn)了許多不妥和錯(cuò)誤之處,誠(chéng)請(qǐng)老師給予指正和教導(dǎo)。
八、參考文獻(xiàn)
【1】、段鐵群 主編 《機(jī)械系統(tǒng)設(shè)計(jì)》 科學(xué)出版社 第一版
【2】、于惠力 主編 《機(jī)械設(shè)計(jì)》 科學(xué)出版社 第一版
【3】、戴 曙 主編 《金屬切削機(jī)床設(shè)計(jì)》 機(jī)械工業(yè)出版社
【4】、戴 曙 主編 《金屬切削機(jī)床》 機(jī)械工業(yè)出版社 第一版
【4】、趙九江 主編 《材料力學(xué)》 哈爾濱工業(yè)大學(xué)出版社 第一版
【6】、鄭文經(jīng) 主編 《機(jī)械原理》 高等教育出版社 第七版
【7】、于惠力 主編 《機(jī)械設(shè)計(jì)課程設(shè)計(jì)》 科學(xué)出版社
附錄:
THE FILE TRANSMISSION GEAR SELECTION
OF THE BASIC PARAMETERS
1, Reasonable choice of module:
Modulus is an important gear basic parameters, the greater the modulus, the greater the tooth thickness, the bending strength of gear is also greater, and its greater carrying capacity. Instead modulus smaller tooth thickness will be thinner, the bending strength of gear will be smaller. The low profile of the gear, due to the low rotational speed, torque, and gear of the relatively large bending stress, so need to choose a larger module in order to ensure its strength. And high-speed file gear, due to the high-speed, torque small gear bending stress is relatively small, so to ensure that the bending strength of gear under the premise of the general selection of the smaller module, so that gear teeth can be increased in order to obtain larger degree of overlap, so as to achieve the purpose of reducing noise.
In a modern gearbox design, the file selection module gear is different. For example, a transmission gear of a file to the five-gear gear module are: 3.5; 3; 2.75; 2.5; 2; to change over the past modulus or modulus of the same can not be the situation of Latin America.
2, a reasonable selection of pressure angle:
When a gear module and set the number of teeth, the gear diameter is determined, and the gear tooth involute base circle depends on the size, the size of the base circle and under pressure angle. For the same pitch circle of gear, if its pitch circle a different pressure angle, base circle is different. When the greater the pressure angle, the base circle diameter of the smaller, more curved involute, tooth root of the tooth will thicken, increase the tooth surface radius of curvature, which can increase the tooth bending strength and contact strength. When reducing the pressure angle, the base will become larger diameter, involute tooth profile will change some of the straight, thinning of the tooth root, tooth smaller radius of curvature, making the tooth bending strength and contact intensity will decrease, but decrease with the pressure angle, to increase the contact ratio gears, reducing the stiffness of the tooth, and can reduce the entry and exit load at the time of engagement, all of which are beneficial to reduce noise. There-fore, low profile gear, often larger pressure angle in order to meet the strength requirements; and regular use of high-speed file smaller gear pressure angle in order to meet the requirements of its lower noise.
For example: a gear module 3, the number of teeth of 30, when the pressure angle of 17.5 degrees for the circular tooth thickness of the base to 5.341; when the pressure angle of 25 degrees, the tooth thickness of the base circle to 6.716; its base circle to increase the tooth thickness 25%, so increase the pressure angle to increase their flexural strength.
3, A reasonable selection of Helix Angle:
Compared with the straight gear, helical gear drive with a smooth, coincidence degree, the impact is small and the advantages of small noise. As a result of the present with synchronous transmission, and transmission will no longer be a direct mobile gear meshing with another gear, but with all the gears are meshing, so that'll bring convenience to the use of helical gear, so to bring the gearbox synchronizer Most of the use of helical gear.
Helical gear as a result of the characteristics of the entire tooth width decision not to enter the mesh at the same time all but one end of first gear into the mesh, with the drive gear along the tooth width direction mesh gradually until all the teeth have wide access to mesh, so the actual meshing helical gear spur the region than the large. When the tooth when a certain width, the contact ratio of helical gear with helix angle increases. Carrying capacity is also stronger, have better stability. In theory, the better helix angle, but the helix angle increases, the axial force will also increase, so that reduces the transmission efficiency.
In the modern design of the gearbox, in order to ensure smooth gear drive, low noise and less impact, all . Files for°gear should choose a larger helix angle, generally about 30 high-speed gear as a result of the higher speed, for a smooth, low impact, low noise, so the use of small modulus, large helical angle; and low-profile gear module using the larger, smaller helix angle.
4, The perspective of a reasonable modification is selected:
With good conditions for the lubrication of the hardened gear is generally believed that the main danger is in the cycle under alternating stress, the fatigue crack Dedendum gradual expansion of the tooth root fracture caused by the failure. Failure in the gear transmission is a part of this. In order to avoid a broken tooth, should be to maximize the tooth root bending strength, and the use is changed, and can achieve this objective. Under normal circumstances, the greater the coefficient, the smaller values tooth, tooth bending stress on the smaller, the higher the bending strength of teeth.
In the hardened gear, the tooth surface pitting failure is one of the reasons off. Increased engagement angle, can reduce the inter-tooth contact stress and maximum slip rates, can greatly increase the ability of anti-pitting. And increased engagement angle, it must have a gear shift is introduced, thereby enhancing contact strength of tooth surface can improve the flexural strength of tooth roots, so as to enhance the effect of the carrying capacity of gears. However, for helical gear drive, variable coefficient is too large, and will total tooth length of the contact line, but to reduce its carrying capacity. At the same time, the greater the coefficient, as a result of tooth to tip increases, the thickness of the tip will be smaller, which will affect the strength of the top teeth.
Therefore, in the design of a modern gearbox, the majority of all reasonable use of gear shift is the angle in order to maximize its advantages. Mainly in the following design criteria:
low profile for the gear pair, the driving gear of the coefficient should be larger than the passive gear shift coefficient, and pair of high-speed profile, the driving gear of the coefficient should be less than passive coefficient gear.
gear with the modification coefficient increased gradually stalls xiajiang. This is because low-grade zones as a result of low rotational speed, torque, and gear for high intensity, so the need to use more of the modification coefficient da.
The total of the gear profile shift coefficient is positive (of the anglel shift as amended), and increased with the stalls and gradually decreased. The smaller the total coefficient, a pair of pair of tooth root of the thickness of the total will be thin, tooth root becomes weak, the lower the bending strength, but decreased as a result of the stiffness of the tooth, easy to absorb shock and vibration, so can reduce the noise. And tooth contact ratio will increase, which bear a single tooth at the time of maximum load Dedendum recent focus distance, the reduced bending moment, which is equivalent to increase the strength of the tooth root, which as a result of thinning and weakened tooth root strength offset factor. Therefore, the greater the overall coefficient, the higher the strength of the tooth root, but the noise may increase. Thus high-speed gear to choose a smaller file of the total coefficient, and low-profile gear must be chosen larger coefficient
5, to improve tip high coefficient:
Top gear in the transmission of high quality factor, the impact of focusing on adaptation, in the main impact of helical gear contact ratio face. Coincidence degree by the end of the formula, we can see that when the number of teeth and meshing certain angle, the tooth tip is affected by tooth pressure angle coefficient of the top high impact factor the greater the high-tip, round tip the greater the pressure angle, contact ratio is The greater and ore stable drive. However, the high coefficient the greater the tip, the thickness of the top teth will become thin, thus affecting the strength tip. At the same time, at least not from the tooth root formula, the high coefficient the greater the tip, at least not the root will increase the number of gear, otherwise, they would have a root cutting. As a result, guarantees of non-root tip-cut and sufficient strength, increased tooth top high coefficient of coincidence degree for the increase is significant.
Top gear in the transmission of high quality factor, the impact of focusing on adaptation, in the main impact of helical gear contact ratio face. Coincidence degree by the end of the formula, we can see that when the number of teeth and meshing certain angle, the tooth tip is affected by tooth pressure angle coefficient of the top high impact factor the greater the high-tip, round tip the greater the pressure angle, contact ratio is The greater and more stable drive. However, the high coefficient the greater the tip, the thickness of the top teeth will become thin, thus affecting the strength tip. At the same time, at least not from the tooth root formula, the high coefficient the greater the tip, at least not the root will increase the number of gear, otherwise, they would have a root cutting. As a result, guarantees of non-root tip-cut and sufficient strength, increased tooth top high coeff-icient of coincidence degree for the increase is significant.
The above is from the module, pressure angle, helix angle, coefficient and a high coefficient of this addendum to an independent analysis of the five aspects of gear design trends. In fact between the various para-meters are inter-related, involved with each other, the choice of transmission parameters, it is necessary to take into account their strengths and weaknesses, but also consider the relationship between them, so in order to maximize their strengths and avoid weaknesses to improve transmission performance.
變速箱各檔齒輪基本參數(shù)的選擇
1、合理選用模數(shù)
模數(shù)是齒輪的一個(gè)重要基本參數(shù),模數(shù)越大,齒厚也就越大,齒輪的彎曲強(qiáng)度也越大,它的承載能力也就越大。反之模數(shù)越小,齒厚就會(huì)變薄,齒輪的彎曲強(qiáng)度也就越小。對(duì)于低速檔的齒輪,由于轉(zhuǎn)速低、扭矩大,齒輪的彎曲應(yīng)力比較大,所以需選用較大的模數(shù),以保證其強(qiáng)度要求。而高速檔齒輪,由于轉(zhuǎn)速高、扭矩小,齒輪的彎曲應(yīng)力比較小,所以在保證齒輪彎曲強(qiáng)度的前提下,一般選用較小的模數(shù),這樣就可以增加齒輪的齒數(shù),以得到較大的重合度,從而達(dá)到降低噪聲的目的。
在現(xiàn)代變速箱設(shè)計(jì)中,各檔齒輪模數(shù)的選擇是不同的。例如,某變速箱一檔齒輪到五檔齒輪的模數(shù)分別是:3.5;3;2.75;2.5;2;從而改變了過(guò)去模數(shù)相同或模數(shù)拉不開(kāi)的狀況。
2、合理選用壓力角
當(dāng)一個(gè)齒輪的模數(shù)和齒數(shù)確定了,齒輪的分度圓直徑也就確定了,而齒輪的漸開(kāi)線齒形取決于基圓的大小,基圓大小又受到壓力角的影響。對(duì)于同一分度圓的齒輪而言,若其分度圓壓力角不同,基圓也就不同。當(dāng)壓力角越大時(shí),基圓直徑就越小,漸開(kāi)線就越彎曲,輪齒的齒根就會(huì)變厚,齒面曲率半徑增大,從而可以提高輪齒的彎曲強(qiáng)度和接觸強(qiáng)度。當(dāng)減小壓力角時(shí),基圓直徑就會(huì)變大,齒形漸開(kāi)線就會(huì)變的平直一些,齒根變薄,齒面的曲率半徑變小,從而使得輪齒的彎曲強(qiáng)度和接觸強(qiáng)度均會(huì)下降,但是隨著壓力角的減小,可增加齒輪的重合度,減小輪齒的剛度,并且可以減小進(jìn)入和退出嚙合時(shí)的動(dòng)載荷,所有這些都有利于降低噪聲。因此,對(duì)于低速檔齒輪,常采用較大的壓力角,以滿足其強(qiáng)度要求;而高速檔齒輪常采用較小的壓力角,以滿足其降低噪聲的要求。
例如:某一齒輪模數(shù)為3,齒數(shù)為30,當(dāng)壓力角為17.5度時(shí)基圓齒厚為5.341;當(dāng)壓力角為25度時(shí),基圓齒厚為6.716;其基圓齒厚增加了25%左右,所以增大壓力角可以增加其彎曲強(qiáng)度。
3、合理選用螺旋角
與直齒輪相比,斜齒輪具有傳動(dòng)平穩(wěn),重合度大,沖擊小和噪聲小等優(yōu)點(diǎn)。現(xiàn)在的變速箱由于帶同步器,換檔時(shí)不再直接移動(dòng)一個(gè)齒輪與另一個(gè)齒輪嚙合,而是所有的齒輪都相嚙合,這樣就給使用斜齒輪帶來(lái)方便,因此帶同步器的變速箱大多都使用斜齒輪。
由于斜齒輪的特點(diǎn),決定了整個(gè)齒寬不是同時(shí)全部進(jìn)入嚙合的,而是先由輪齒的一端進(jìn)入嚙合,隨著輪齒的傳動(dòng),沿齒寬方向逐漸進(jìn)入嚙合,直到全部齒寬都進(jìn)入嚙合,所以斜齒輪的實(shí)際嚙合區(qū)域比直齒輪的大。當(dāng)齒寬一定時(shí),斜齒輪的重合度隨螺旋角增加而增加。承載能力也就越強(qiáng),平穩(wěn)性也就越好。從理論上講,螺旋角越大越好,但螺旋角增大,會(huì)使軸向分力也增大,從而使得傳遞效率降低了。
在現(xiàn)代變速箱的設(shè)計(jì)中,為了保證齒輪傳動(dòng)的平穩(wěn)性、低噪聲和少?zèng)_擊,所有齒輪都要選擇較大的螺旋角,一般都在30°左右。對(duì)于高速檔齒輪由于轉(zhuǎn)速較高,要求平穩(wěn),少?zèng)_擊,低噪聲,因此采用小模數(shù),大螺旋角;而低速檔齒輪則用較大模數(shù),較小螺旋角。
4、合理選用正角度變位
對(duì)于具有良好潤(rùn)滑條件的硬齒面齒輪傳動(dòng),一般認(rèn)為其主要危險(xiǎn)是在循環(huán)交變應(yīng)力作用下,齒根的疲勞裂紋逐漸擴(kuò)張?jiān)斐升X根斷裂而失效。變速箱中齒輪失效正是屬于這一種。為了避免輪齒折斷,應(yīng)盡量提高齒根彎曲強(qiáng)度,而運(yùn)用正變位,則可達(dá)到這個(gè)目的。一般情況下,變位系數(shù)越大,齒形系數(shù)值就越小,輪齒上彎曲應(yīng)力越小,輪齒彎曲強(qiáng)度就越高。
在硬齒面的齒輪傳動(dòng)中,齒面點(diǎn)蝕剝落也是失效原因之一。增大嚙合角,可降低齒面間的接觸應(yīng)力和最大滑動(dòng)率,能大大提高抗點(diǎn)蝕能力。而增大嚙合角,則必須對(duì)一副齒輪都實(shí)行正變位,這樣既可提高齒面的接觸強(qiáng)度,又可提高齒根的彎曲強(qiáng)度,從而達(dá)到提高齒輪的承載能力效果。但是,對(duì)于斜齒輪傳動(dòng),變位系數(shù)過(guò)大,又會(huì)使輪齒總的接觸線長(zhǎng)度縮短,反而降低其承載能力。同時(shí),變位系數(shù)越大,由于齒頂圓要隨之增大,其齒頂厚度將會(huì)變小,這會(huì)影響齒頂?shù)膹?qiáng)度。
因此在現(xiàn)代變速箱的設(shè)計(jì)中,大多數(shù)齒輪均合理采用正角度變位,以最大限度發(fā)揮其優(yōu)點(diǎn)。主要有以下幾個(gè)設(shè)計(jì)準(zhǔn)則:
l 對(duì)于低速檔齒輪副來(lái)說(shuō),主動(dòng)齒輪的變位系數(shù)應(yīng)大于被動(dòng)齒輪的變位系數(shù),而對(duì)高速檔齒輪副,其主動(dòng)齒輪的變位系數(shù)應(yīng)小于被動(dòng)齒輪的變位系數(shù)。
l 主動(dòng)齒輪的變位系數(shù)隨檔位的升高而逐漸下降。這是因?yàn)榈蜋n區(qū)由于轉(zhuǎn)速低、扭矩大,齒輪強(qiáng)度要求高,因此需采用較da的變位系數(shù)。
l 各檔齒輪的總變位系數(shù)都是正的(屬于角變位修正),而且隨著檔位的升高而逐漸減小??傋兾幌禂?shù)越小,一對(duì)齒輪副的齒根總的厚度就越薄,齒根就越弱,其抗彎強(qiáng)度就越 低,但是由于輪齒的剛度減小,易于吸收沖擊振動(dòng),故可降低噪聲。而且齒形重合度會(huì)增加,這使得單齒承受最大載荷時(shí)的著力點(diǎn)距齒根近,使得彎曲力矩減小,相當(dāng)于提高了齒根強(qiáng)度,這對(duì)由于齒根減薄而消弱強(qiáng)度的因素有所抵消。所以總變位系數(shù)越大,則齒根強(qiáng)度越高,但噪聲則有可能增大。因此高速檔齒輪要選擇較小的總變位系數(shù),而低速檔齒輪則必須選用較大的總變位系數(shù)。
5、提高齒頂高系數(shù)
齒頂高系數(shù)在傳動(dòng)質(zhì)量指標(biāo)中,影響著重合度,在斜齒輪中主要影響端面重合度。由端面重合度的公式可知,當(dāng)齒數(shù)和嚙合角一定時(shí),齒頂圓壓力角是受齒頂高系數(shù)影響的,齒頂高系數(shù)越大,齒頂圓壓力角也越大,重合度也就越大,傳動(dòng)也就越平穩(wěn)。但是,齒頂高系數(shù)越大,齒頂厚度就會(huì)越薄,從而影響齒頂強(qiáng)度。同時(shí),從最少不根切齒數(shù)公式來(lái)看,齒頂高系數(shù)越大,最少不根切齒數(shù)就會(huì)增加,否則的話,就會(huì)產(chǎn)生根切。因此,在保證不根切和齒頂強(qiáng)度足夠的情況下,增大齒頂高系數(shù),對(duì)于增加重合度是有意義的。
因此在現(xiàn)代變速箱的設(shè)計(jì)中,各檔齒輪的齒頂高系數(shù)都選擇較大的值,一般都大于1.0,稱(chēng)為細(xì)高齒,這對(duì)降低噪聲,增加傳動(dòng)平穩(wěn)性都有明顯的效果。對(duì)于低速檔齒輪,為了保證其具有足夠的齒根彎曲強(qiáng)度,一般選用較小的齒頂高系數(shù);而高速檔齒輪,為了保證其傳動(dòng)的平穩(wěn)性和低噪聲,一般選用較大的齒頂高系數(shù)。
以上是從模數(shù)、壓力角、螺旋角、變位系數(shù)和齒頂高系數(shù)這五個(gè)方面去獨(dú)立分析齒輪設(shè)計(jì)趨勢(shì)。實(shí)際上各個(gè)參數(shù)之間是互相影響、互相牽連的,在選擇變速箱的參數(shù)時(shí),既要考慮它們的優(yōu)缺點(diǎn),又要考慮它們之間的相互關(guān)系,從而以最大限度發(fā)揮其長(zhǎng)處,避免短處,改善變速箱的使用性能。
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