2012-2013-2《數字邏輯設計及應用》期末考試題-A參考解答.doc
《2012-2013-2《數字邏輯設計及應用》期末考試題-A參考解答.doc》由會員分享,可在線閱讀,更多相關《2012-2013-2《數字邏輯設計及應用》期末考試題-A參考解答.doc(7頁珍藏版)》請在裝配圖網上搜索。
學院 姓名 學號 任課老師 考場教室__________選課號/座位號 ………密………封………線………以………內………答………題………無………效…… 電子科技大學2012 -2013學年第 二 學期期 末 考試 A 卷 課程名稱:_數字邏輯設計及應用__ 考試形式: 閉卷 考試日期: 20 13 年 07 月 05 日 考試時長:_120___分鐘 課程成績構成:平時 30 %, 期中 30 %, 實驗 0 %, 期末 40 % 本試卷試題由___七__部分構成,共__7___頁。 題號 一 二 三 四 五 六 七 八 九 十 合計 得分 得 分 I. Fill out your answers in the blanks (3’ X 10=30’) 1. If a 74x138 binary decoder has 110 on its inputs CBA, the active LOW output Y5 should be ( 1 or high ). 2. If the next state of the unused states are marked as “don’t-cares” when designing a finite state machine, this approach is called minimal ( cost ) approach. 3.The RCO_L of 4-bit counter 74x169 is ( 0 or low ) when counting to 0000 in decreasing order. 4. To design a "001010" serial sequence generator by shift registers, the shift register should need ( 4 ) bit at least. 5. One state transition equation is Q*=JQ’+K’Q. If we use T flip-flop with enable to complete the equation,the enable input of T flip-flop should have the function EN=( JQ’+KQ ). 6. A 4-bit Binary counter can have ( 16 ) normal states at most, 4-bit Johnson counter with no self-correction can have ( 8 ) normal states, 4-bit linear feedback shift-register (LFSR) counter with self-correction can have ( 16 ) normal states. 7. If we use a ROM, whose capacity is 16 4 bits, to construct a 4-bit binary code to gray code converter, when the address inputs are 1001, ( 1101 ) will be the output. 8. When the input is 10000000 of an 8 bit DAC, the corresponding output voltage is 2V. The output voltage is ( 3.98 ) V when the input is 11111111. 得 分 II. Please select the only one correct answer in the following questions.(2’ X 5=10’) 1. If a 74x85 magnitude comparator has ALTBIN=1, AGTBIN=0, AEQBIN=0, A3A2A1A0=1101, B3B2B1B0=0111 on its inputs, the outputs are ( D ). A) ALTBOUT=0, AEQBOUT=0, AGTBOUT=0 B) ALTBOUT=1, AEQBOUT=0, AGTBOUT=0 C) ALTBOUT=1, AEQBOUT=0, AGTBOUT=1 D) ALTBOUT=0, AEQBOUT=0, AGTBOUT=1 2. As shown in Figure 1, what would the outputs of the 4-bit adder 74x283 be ( B ) when A3A2A1A0=0100, B3B2B1B0=1110 and S/A=1. A) C4=1, S3S2S1S0=0010 B) C4=0, S3S2S1S0=0110 C) C4=0, S3S2S1S0=1010 D) C4=0, S3S2S1S0=1110 Figure 1 3. Which of the following statements is INCORRECT? ( A ) A) A D latch is edge triggered and it will follow the input as long as the control input C is active low. B) A D flip flop is edge triggered and its output will not change until the edge of the controlling CLK signal. C) An S-R latch may go into metastable state if both S and R are changing from 11 to 00 simultaneously. D) The pulse applying to any input of an S -R latch must meet the minimum pulse width requirement. 4. The capacity of a memory that has 13 bits address bus and can store 8 bits at each address is ( B ). A) 8192 B) 65536 C) 104 D) 256 5. Which state in Figure 2 is NOT ambiguous ( C ). A) A B) B C) C and D D) C Figure 2 得 分 III. Analyze the sequential-circuit as shown in Figure 3, D Flip-Flop with asynchronous preset and clear inputs. [15’] 1.Write out the excitation equations, transition equations and output equation. [5’] 2.Assume the initial state Q2Q1=00, complete the timing diagram for Q2 ,Q1 and Z. [10’] Figure 3 參考答案: 激勵方程: D1=Q2/,D2= Q1 轉移方程:Q1 *= D1=Q2/,Q2 *=D2= Q1 輸出方程:Z= (CLK+Q2)/ 參考評分標準: 1. 5個方程正確得5分;每錯一個扣1分,扣完5分為止; 2. Q1、Q2、Z的波形邊沿判斷正確,得3分,錯一個,扣1分,扣完3分為止;每個上升沿和下降沿各0.5分,錯1處扣0.5分,扣完7分為止。 得 分 IV. Analyze the sequential-circuit as shown below, which contains two 74x163 4-bit binary counter. [15’] 1. Write out the logic expression LD_L for U1 and CLR_L for U2.[4’] 2. Assume the initial state is 310, write out the state sequence for the circuit. [8’] 3. Describe the modulus for the circuit. [3’] The function table for 74x163 Inputs Current state Next state Outputs CLR_L LD_L ENT ENP QD QC QB QA QD* QC* QB* QA* RCO 0 X X X X X X X 0 0 0 0 0 1 0 X X X X X X D C B A 0 1 1 0 X X X X X QD QC QB QA 0 1 1 X 0 X X X X QD QC QB QA 0 1 1 1 1 0 0 0 0 0 0 0 1 0 1 1 1 1 0 0 0 1 0 0 1 0 0 1 1 1 1 0 0 1 0 0 0 1 1 0 1 1 1 1 0 0 1 1 0 1 0 0 0 1 1 1 1 …………. ………….. 0 1 1 1 1 1 1 1 1 0 0 0 0 1 參考評分標準: 1. LD_L=Q3/,CLR_L=(Q5Q4Q3)/ [4’] 2. 狀態(tài)序列:十六進制數表示:03,…08,13,…18,23,…28,33,…38,03,…08 或十進制數表示:3,…8,19,…24,35,…40,51,…56,3,…8[8’] 錯1處扣1分,扣完為止。 3. m=24 [3’] 得 分 V. Design a sequence signal generator with self-correcting to generate a serial output sequence of 101100, using a 74x194 and a 74x151.[15’] 1. List the transition table .[4’] 2. Write out the canonical sum of feedback function LIN.[[4’] 3. Draw the circuit diagram.[7’] The function table for 74x194 Iutputs Next state Function S1 S0 QA* QB* QC* QD* 0 0 0 1 1 0 1 1 QA QB QC QD RIN QA QB QC QB QC QD LIN A B C D Hold Shift right Shift left Load 參考評分標準: 1. 轉移表正確4分,錯1行扣0.5分。 2. 反饋函數正確LIN=D0=∑m(0,2,4,5) [4’] 3. 電路圖正確7分,錯1處扣0.5分,扣完為止。 得 分 VI. Write out the state/output table for a Mealy machine that can detect the pattern 10101 or 10111 . The output Z=1 when the pattern is detected. Your model should also be able to detect overlapping sequences. (10’) State meaning S X 0 1 Initial state A A, 0 B, 0 Got 1 B C, 0 B, 0 Got 10 C A, 0 D, 0 Got 101 D E, 0 F, 0 Got 1010 E A, 0 D, 1 Got 1011 F C, 0 B, 1 S*, Z 評分標準: 1.狀態(tài)定義正確得3分;每錯一處扣0.5分,扣完3分為止; 2.狀態(tài)轉移正確,得5分;每錯一處扣0.5分,扣完5分為止; 3.輸出正確,得2分;每錯一處扣0.5分,扣完2分為止。 得 分 VII. Design a code converter with 2421 code to 8421 code,using a 74x85, a 74x283 and some gates if needed. [10’] 參考評分標準: 1.74x85級聯(lián)輸入端連接正確2分,比較值正確3分,74x283的C0端連接正確1分; 2.74x85的A3~A0與74x283的A3~A0連接正確2分; 3.74x85與74x283中間連接的電路正2分。 第 7 頁 共 7 頁- 配套講稿:
如PPT文件的首頁顯示word圖標,表示該PPT已包含配套word講稿。雙擊word圖標可打開word文檔。
- 特殊限制:
部分文檔作品中含有的國旗、國徽等圖片,僅作為作品整體效果示例展示,禁止商用。設計者僅對作品中獨創(chuàng)性部分享有著作權。
- 關 鍵 詞:
- 數字邏輯設計及應用 2012 2013 數字 邏輯設計 應用 期末 考試題 參考 解答
裝配圖網所有資源均是用戶自行上傳分享,僅供網友學習交流,未經上傳用戶書面授權,請勿作他用。
鏈接地址:http://www.3dchina-expo.com/p-8866817.html